Frage 4 / Antwort D |
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Das Löslichkeitsprodukt von Bariumsulfat ist definiert als: |
L |
= |
c (Ba2+) · c (SO42-) |
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10-10 mol2/l2 |
= |
c (Ba2+) · c (SO42-) |
c (Ba2+) = c (SO42-) |
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10-10 mol2/l2 |
= |
c2 (Ba2+) |
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c(Ba2+) |
= |
c(SO42-) |
= |
10-5 mol/l |
BaSO4: 233 g/mol |
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233 g · 10-5 |
= |
2,33 g · 10-3 |
= |
2,33 mg |
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